# Monthly GRE Challenge Problem 1 – Answer to Win Free Access

Here is the solution and the winners ðŸ™‚

**ANSWER THIS QUESTION TO WIN!**

At the end of this month, I will choose one person out of all those who answered this correctly and give Free 1 month access to my 10 GRE Quantitative Quizzes – each quiz contains 20 questions and you will have a total of 200 questions to practice on.

**Note: Put your answers in the comment box below.**

Here is the question:

x=120

x=120

60

x=60

120

90

x=105Draw chord BC to get an inscribed quadrilateral ABCD. Angle C should be 75 (one of the equal angles in the isoceles triangle BCD)

For an inscribed quadrilateral, opposite angles sum up to 180. Hence, x is 180-75 = 105105 degrees I guess cyclic quadrilateral will be used.

x=90

120

solved it by making an isosceles trapeoid..

X=75

105

120

x = 105

108

60

120

X= 105 because it is cyclic quad

My answer is x=90 Degree

x = 90

75

120

can’t be determined

90

120

75

105

120

120 is right answer

75

90

Final Answer: 105 degrees

120

75 degrees

90

Cannot be determined

105

105

105

105

Answer: 150

Answer: 105, Sorry 150 is by mistake…

I think it would be 60. Central angle is twice the inscribed opposite angle ! I think we will use this theorem here!

angle x= 30 degrees

108….i made it into a regular pentagon since BD equals CD… and interior angle of a pentagon is 108 degrees!

75

x=105

30*2=60

180-30=150

150/2=75

75*2=150

150+150+60=360

150+60=210

210/2=105