# 5 Hardest GRE Questions

Since GRE test takers in Pakistan are always asking me for hard GRE questions, I have selected some of my favourite questions. All of these questions are 165+ level questions and similar questions have shown up on the GRE exam to high scorers. Answers to these questions will be available next week – meanwhile you can start solving these and you may put your answers in the comment box below. Good Luck!

1. D

2.D

3.D

That’s what I got

A1=12

A2=4214

A3=90

1)12

2)4214

3)70

4)E

5) tumult , relegate, vindictive

Please anyone shed some light on Verbal. Have my exam on 30th march :p

12

4214

70

E

Tumult relegate vindictive

Please shed some light on verbal. I have my exam on monday:p

1) x=180-y ===> x=180-5x

simplifying results x=30

sum of exterior angles always equal to 360 degree. Also number of exterior angles equal to number of sides. Hence, 360/30=12 sides, option D

2) Sum of numbers from 1-100=5050

Sum of even numbers b/w 25-63=836

Hence, 5050-836=4,214, Option D

3) 5C2 *4= 40 triangles, Option C

4) Just a fluke,.. may be option E

5) Idiosyncrasy, discern, vindictive

3) (5C2*4C1)+(4C2*5C1)=70

Yea. Abdullah, you’re only looking at an option where you take 2 points from the 5-point line and 1 point from the other line. But, you can also take 2 points out of the 4 points and the 3rd one from 5 points.

So, that’s what YASH does, he adds up the total count from both of the options.

1. 12

2. 4214

3. 70

4. C

5. Idiosyncrasy, discern, vindictive

The sum of interior angles of a regular polygon=(n-2)*180.

So the measure of each angle=(1/n)(n-2)*180.

In this problem, we have find n.

Since x+y=180

or x+5x=180

or 6x=180

or x=180/5=30

Therefore, y=5x=5*30=150.

Now (1/n)(n-2)*180=150

or (n-2)*180=150n

or 180n-360=150n

or 180n-150n=360

or 30n=360

Therefore n=360/30=12

Answer to Q.1: (D) 12.

Can we assume x+y=180? that its a straight line?

Yup

Answer to Q2: Even integers between 25 and 63 have to be omitted.

The number of integers between 25 and 63 =(1/2)(63-25)=(1/2)*38=19.

Sum of the omitted even omitted integers=(19/2)(2*26+(19-1)*2)=(19/2)2(26+18)=19*44

=836.

Sum of all numbers from 1 to 100=(100/2)(2*1+(100-1)1)=(50)(101)=5050.

Therefore, the sum of the integers from 1 and 100 inclusive, with the even integers between 25 and 63 omitted=5050-836=4214.

Answer to Q3: In order to form a triangle we have to take three points. We may either take any 2 points from 5-point line and the remaining 1 point from 4-p0int line, OR, we may take 1 point from the 5-point line and 2 points from the 4-point line.

Therefore, using combination formula we have 5C2*4C1+5C1*4C2=40+30=70.

Answer: (D) 70.

for question 5: B, E, I

Question 4 is almost certainly D, correct? There is no reference to another industry besides the Machine-Tool industry and the passage states that the author “Examines the transformation of the Machine Tool industry” (history) and that he approaches the topic “From a Marxist perspective” (Ideological). I can’t find any evidence of a comparison or that this shows the origin of some industrial phenomenon, and choice C is a better description of the commentary that we are reading than it is “Forces of Nature” itself.

Are we to take from the answer choices in Question 3 that the GRE does not consider flat triangles to be triangles? 70 is only correct if we cannot take 3 points from the same line.

Yes GRE does not consider flat or straight lines to be triangles

For question 5 BDH

What is the combination formula for #3? I understand the concept I just don’t have the formula.